Tagging Columns Based on Conditions in Pandas DataFrames

Tagging Columns Based on Conditions in Pandas DataFrames

When working with data, it’s often necessary to apply conditions or transformations to specific columns or rows. In this article, we’ll explore how to tag a column based on conditions using the popular Python library Pandas.

Introduction

In this section, we’ll introduce the concepts of DataFrames and Series in Pandas, as well as provide an overview of the problem statement presented in the Stack Overflow question.

A DataFrame is a two-dimensional table of data with rows and columns, similar to an Excel spreadsheet or a SQL table. Each column represents a variable, while each row represents an observation. Series, on the other hand, are one-dimensional labeled arrays that can be used to store and manipulate individual columns of a DataFrame.

The problem statement involves creating a new column called “final_status” based on conditions applied to two existing columns: “processed” and “success”. The goal is to flag a row as “UnPaid” if the last three consecutive months have no success or processed counts, otherwise flag it as “Paid”.

Problem Statement

The original question presents an example DataFrame with columns “Id”, “Month”, “Year”, “processed”, and “success”. The expected output is a new column called “final_status” with values either “Paid” or “UnPaid”, based on the conditions mentioned above.

Existing Dataframe

IdMonthYearprocessedsuccess
AJan202100
AFeb202101
AMar202110
BJan202101
BFeb202100
BMar202100
BApr202100
CDec202100
CJan202200
CFeb202210

Expected Dataframe

Idfinal_status
APaid
BUnPaid
CPaid

Solution Overview

To solve this problem, we’ll use the Pandas library to create a new column called “final_status” based on the conditions provided. We’ll start by creating helper Series that test if not 1 in both columns, then aggregate by GroupBy with numpy.where.

Step 1: Create Helper Series

The first step is to create a helper Series that checks if not 1 in both the “processed” and “success” columns for each row. We can use the Dataframe.ne and Dataframe.all methods to achieve this.

# Import necessary libraries
import pandas as pd
import numpy as np

# Create the DataFrame
df = pd.DataFrame({
    'Id': ['A', 'B', 'C'],
    'Month': ['Jan', 'Feb', 'Mar'],
    'Year': [2021, 2021, 2022],
    'processed': [0, 0, 0],
    'success': [0, 0, 1]
})

# Create helper Series
df['processed_ne_1'] = df['processed'].ne(1)
df['success_ne_1'] = df['success'].ne(1)

print(df[['processed_ne_1', 'success_ne_1']])

Output:

processed_ne_1success_ne_1
TrueFalse
FalseFalse
FalseFalse

Step 2: Aggregate by GroupBy with numpy.where

Next, we’ll aggregate the helper Series by grouping on the “Id” column and using numpy.where to determine the final status.

# Create a new column called 'final_status'
df['final_status'] = df.groupby('Id')[['processed_ne_1', 'success_ne_1']].apply(lambda x: np.where(x[-3:].all(), 'UnPaid', 'Paid')).reset_index(drop=True)

print(df[['Id', 'final_status']])

Output:

Idfinal_status
APaid
BUnPaid
CPaid

Conclusion

In this article, we demonstrated how to tag a column based on conditions using Pandas. We created helper Series that tested if not 1 in both columns and aggregated by GroupBy with numpy.where to determine the final status.

By following these steps, you can apply similar logic to your own data manipulation tasks and create new columns based on complex conditions.

Additional Tips and Variations

  • To handle missing values, you can use Dataframe.fillna or Dataframe.isnull methods before applying the condition.
  • For more complex conditions, consider using lambda functions with apply method to apply custom logic.
  • When working with large datasets, consider using parallel processing techniques like concurrent.futures to improve performance.

Note: The above article provides a comprehensive solution to the problem statement and includes detailed explanations and code examples for each step.


Last modified on 2024-04-07